Question

Find the smallest number which is completely divisible by 28 and 42.

• A. 48
• B. 28
• C. 84
• D. 14

Answer 1

The correct option is C

84

The smallest number that is completely divisible by 28 and 42 is LCM of the two numbers.

$\begin{array}{cc}2& 28,42\\ 2& 14,21\\ 3& 7,21\\ 7& 7,7\\ & 1,1\end{array}$

Hence LCM of 28 and 42 is $2\times 2\times 3\times 7=84$