CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the smallest number which when divided by 23, 45, 5, 27 and 48 leaves a remainder 7.


A

49687

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

49677

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

98607

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

68787

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

49687


The LCM of the given numbers is 49680 which means when this number divided by the given numbers will give a remainder zero. So in order to get number which leaves a remainder of 7 when divided by 23, 45, 5, 27, 48 we have to add 7 to 49680. The number which is required is 49687.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Fundamental Theorem of Arithmetic
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon