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Byju's Answer
Standard IX
Mathematics
(x±a)(x±b) = x²±(a+b)x+ab.
Find the solu...
Question
Find the solution of
15
(
x
−
1
)
+
4
(
x
+
3
)
=
2
(
7
+
x
)
Open in App
Solution
15
(
x
−
1
)
+
4
(
x
+
3
)
=
2
(
7
+
x
)
⇒
15
x
−
15
+
4
x
+
12
=
14
+
2
x
⇒
15
x
+
4
x
−
15
+
12
=
2
x
+
14
⇒
19
x
−
3
=
2
x
+
14
Adding
−
2
x
+
3
both sides, we get
⇒
19
x
−
3
−
2
x
+
3
=
2
x
+
14
−
2
x
+
3
⇒
17
x
=
17
⇒
x
=
17
17
∴
x
=
1
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1
Similar questions
Q.
Solve the following equation:
15
(
x
−
1
)
+
4
(
x
+
3
)
=
2
(
7
+
x
)
Q.
Find the solutions of the following equations which have common roots:
4
x
4
+
12
x
3
−
x
2
−
15
x
=
0
,
6
x
4
+
13
x
3
−
4
x
2
−
15
x
=
0
.
Q.
3
4
x
+
1
=
(
27
)
x
+
1
find x.
Q.
If
3
4
x
+
1
=
(
27
)
x
+
1
, then find
x
.
Q.
Find the LCM of the following:
2
x
3
+
15
x
2
+
2
x
−
35
,
x
3
+
8
x
2
+
4
x
−
21
whose GCD is
x
+
7
.
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Standard IX Mathematics
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