Find the solution to the following system of linear equations:
2p+3q=9
p - q = 2
(3, 1)
2p + 3q = 9 …. (I)
p - q = 2…(II)
From the equation II, we get, p = 2 + q
Substituting this value of p in equation I we get,
2(2 + q) +3q=9
⇒ 4+5q=9
⇒ 5q= 5
⇒ q=1
Substituting this value of q in equation II we get,
P – 1=2
⇒ p=3
Hence the solution is (3, 1).