Question

Find the sum:
$-2\frac{1}{3}+4\frac{3}{5}$

Answer 1

$-2\frac{1}{3}+4\frac{3}{5}=\frac{-7}{3}+\frac{23}{5}=\frac{-7\times 5}{3\times 5}+\frac{23\times 3}{5\times 3}[\because \text{LCM of}3\text{and}5=15]=\frac{-35}{15}+\frac{69}{15}=\frac{-35+69}{15}=\frac{34}{15}=2\frac{4}{15}$