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Question

Find the sum:
213+114+256+3712

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Solution

We have:


213 + 114 + 256 + 3712 = 73 + 54 + 176 + 4312 L.C.M. of 3, 4, 6 and 12 = (2 × 2 × 3) = 12 = 28 + 15 + 34 + 4312 12 ÷ 3 = 4, 4 × 7 = 28, 12 ÷ 4 = 3, 3 × 5 = 15, 12 ÷ 6 =2, 2 × 17 = 34 and 12 ÷ 12 = 1, 1 × 43 = 43 = 12010121 = 10
234+556

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