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Question

Find the sum : 34 + 32 + 30 + .... + 10


A

300

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B

286

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C

310

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D

240

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Solution

The correct option is B

286


34+32+30+....+10
This sequence is an AP.
Here, a=34,d=3234=2.
Let the number of terms of the AP be n.
We know that
an=a+(n1)d.

10=34+(n1)(2)

(n1)(2)=24

n1=242=12

n=13

Also, we know that the sum to n terms of an AP with first term a and last term l is given by

Sn=n2(a+l).

S13=132(34+10)

S13=286

Hence, the required sum is 286.


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