Question

# Find the sum:$$34+32+30+......+10$$

Solution

## In the given series $$34+32+30+......+10$$ the first term is $$34$$ and common difference is $$-2$$.Let us assume there are $$n$$ terms.Then $$n$$ th term is $$10$$.Then $$34+(n-1)(-2)=10$$or, $$-2(n-1)=-24$$or, $$n=13$$.Now the sum of the series is $$=\dfrac{13}{2}(10+34)$$$$=286$$.Mathematics

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