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Question

Find the sum of 10 terms of the series whose nth term is 3.2n.


Solution

Given tn = 3.2n.

Sum of the n terms

    Sn=ni=13.2n  

          = 3 [21+22+23+......nterms]

        Given series is a GP

        Sum of n terms 

           Sn = 3. [2.(2n1)(21)]-------------(1)

        For 10 terms substitute n = 10 in equation 1

           S10 = 3. [2.(2101)(21)] = 3.[2 × (1023)] = 6144

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