Find the sum of $6 x^{3} - 7 x^{2} 2 x + 4$ and $9 x^{3} - 5 x^{2} - 4 x + 6$ . Subtract it from the sum of $3 x^{3} + 2 x^{2} - 9$ and $4 x^{3} + 7$ .

Open in App

Solution

$\begin{matrix} \Rightarrow (6 x^{3} - 7 x^{2} + 2 x + 4) + (9 x^{3} - 5 x^{2} - 4 x + 6) \Rightarrow (6 x^{3} + 9 x^{3}) + (- 7 x^{2} - 5 x^{2}) + (2 x - 4 x) + 10 s u m 1 = 15 x^{3} - 12 x^{2} - 2 x + 10 s u m 2 = (3 x^{3} + 2 x^{2} - 9) + (4 x^{3} + 7) 7 x^{3} + 2 x^{2} - 2 - (15 x^{3} - 12 x^{2} - 2 x + 10) = - 8 x^{3} + 14 x^{2} + 2 x - 12 \end{matrix}$

Suggest Corrections

Similar questions

6 x^{3} - 5 x^{2} + 4 x - 2

x + 2 x^{2} - 3 x^{3}

2 - x^{2} + 6 x - x^{3}

4 + 3 x

5 - 4 x + 2 x^{2}

3 x^{3} - 5 x

- x^{2} + 2 x + 5

1 + x + 2 x^{2} - 3 x^{3}

2 x^{2} - 4 x^{3} + 4 x + 9

Subtract $(5 x^{2} - 5 x - 7)$ from the sum of $(x^{2} - 3), (5 - 4 x)$ and $(9 + 4 x^{2})$

4 x^{3} - 5 x^{2} + 6

3 x^{3} - 7 x^{2} - 5