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Question
Find the sum of all even intergers between 101 and 999.
Find the sum of all even intergers between 101 and 999.
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Solution
Sum of first 'n' even integers = n(n+1)
sum of all even intergers between 101 and 999
= Sum of all even integers between 1 and 999- sum of all even integers between 1 and 101
= 999(999+1) - 101(101+1)
= 999(1000)-101(102)
=999000-10302=988698
sum of all even intergers between 101 and 999
= Sum of all even integers between 1 and 999- sum of all even integers between 1 and 101
= 999(999+1) - 101(101+1)
= 999(1000)-101(102)
=999000-10302=988698
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