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Question

Find the sum of first 24 terms of an AP whose nth term is given by an=3+2n.


A

568

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B

624

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C

564

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D

672

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Solution

The correct option is D

672


Given,
an=3+2n
So, First term = a1=3+2×1=5
Last term = a24=3+2×24=51

We know, sum of n terms is given by
Sn=n2(a+l)

To find S24, we have n=24, a1=5,a24=51

S24=242(5+51)

=12(56)=672


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