Question

Find the sum of interior angles of a polygon with:
$9$ sides

Answer 1

$9$ sides

Number of sides $n=9$

The sum of interior angles of polygon $=(2n-4)\times {90}^o$

$=(2\times 9-4)\times {90}^o$

$=(18-4)\times {90}^o$

$=14\times {90}^o$

We get,

$={1260}^o$