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Question

Find the sum of interior angles of a polygon with:
$$9$$ sides


Solution

$$9$$ sides
Number of sides $$n=9$$
The sum of interior angles of polygon $$=(2n-4)\times 90^o$$
$$=(2\times 9-4) \times 90^o$$
$$=(18-4) \times 90^o$$
$$=14 \times 90^o$$
We get,
$$=1260^o$$

Mathematics

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