Question

Find the sum of measures of all interior angles of a polygon with the number of sides:
12

Answer 1

We know that,
Sum of measures of all interior angles of 12 sided polygons $=(2n-4)\times {90}^{\circ }$
Where, $n=12$
$\begin{array}{c}=\left(\right(2\times 12)-4)\times {90}^{\circ }\\ =(24-4)\times {90}^{\circ }\\ =20\times {90}^{\circ }\\ ={1800}^{\circ }\end{array}$