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Question

Find the sum of measures of all interior angles of a polygon with the number of sides:
12


Solution

We know that, 
Sum of measures of all interior angles of 12 sided polygons $$ =(2 n-4) \times 90^{\circ} $$ 
Where, $$ n=12 $$
$$\begin{array}{l}=((2 \times 12)-4) \times 90^{\circ} \\=(24-4) \times 90^{\circ} \\=20 \times 90^{\circ} \\=1800^{\circ}\end{array}$$

Mathematics

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