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Question

Find the sum of the first 15 multiples of 8.

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Solution

The first 8 multiples of 8 are
8, 16, 24, 32, 40, 48, 56,64.......120
These are in an A.P., having first term as 8 and common difference as 8.
Therefore, a = 8
d = 8
S15 = ?
Sn = n2[2a + (n - 1)d]
S15 = 152 ​​​​[2(8) + (15 - 1)8]
S15 = 7.5[6 + (14) (8)]
S15 = 7.5[16 + 112]
S15 = 7.5(128)
S15 = 960


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