Find the third measure of each parallelogram having measures as given below:
Base Altitude Area
$1.2 d m$ $? d m$ $1.08$ $s q . d m$

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Solution

Area of parallelogram $= b a s e \times a l t i t u d e$
Area $1.08$ $s q . d m$ ;base $1.2 d m$
Altitude of parallelogram $= \frac{A r e a}{B a s e}$
Altitude of parallelogram $= \frac{1.08}{1.2} = 0.9 d m$
Hence, altitude of parallelogram is $0.9 d m$ .

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