Find the third measure of each parallelogram having measures as given below:
Base Altitude Area
$13 \frac{1}{4} c m$ $1 \frac{1}{2} c m$ ? $s q . c m$

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Solution

Area of parallelogram $= b a s e \times a l t i t u d e$
Base $13 \frac{1}{4} c m$ and altitude $1 \frac{1}{2} c m$
Area of parallelogram $= \frac{53}{4} \times \frac{3}{2} = 19 \frac{7}{8} c m^{2}$
Hence, area of parallelogram is $19 \frac{7}{8} c m^{2}$

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