Find the third measure of each parallelogram having measures as given below:
Base Altitude Area
$32 c m$ $17 c m$ ? $s q . c m$

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Solution

Area of parallelogram $= b a s e \times a l t i t u d e$
Base $32 c m$ and altitude $17 c m$
Area of parallelogram $= 32 \times 17 = 544 c m^{2}$
Hence, area of parallelogram is $544 c m^{2}$

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17

(Given: \sqrt{2} = 1.414)

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