    Question

# Find the total number of divisors, sum of all factors and product of all factors of 11760.

A
Total number of factors : 40
Sum of factors : 42440
Product of factors : 1176020
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B
Total number of factors : 60
Sum of factors : 42480
Product of factors : 1176020
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C
Total number of factors : 40
Sum of factors : 42440
Product of factors : 1176020
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D
Total number of factors : 60
Sum of factors : 42408
Product of factors : 1176040
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Solution

## The correct option is D Total number of factors : 60 Sum of factors : 42408 Product of factors : 1176040Let N=11760=24×3×3×5×72 Then, total number of factors or divisors of N=(4+1)(1+1)(1+1)(2+1) =5×2×2×3=60 Sum of all the factors of N=24−1−12−1×32−13−1×52−15−1×73−17−1 =31×82×6×3426=31×4×6×57=42408 Product of all factors of N=(N)Totaldivisors2 =(11760)602=(11760)30  Suggest Corrections  0      Similar questions
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