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Question

Find the trigonometric ratio equivalent to the following:

sin55+cos20+cot70+cosec85


  1. cos35° + sin70° + tan20° + sec5°

  2. cos35° + sin20° + tan20° + sec5°

  3. cos35° + sin20° + tan70° + sec5°

  4. cos35° + sin20° + tan70° + sec85°


Solution

The correct option is A

cos35° + sin70° + tan20° + sec5°


Since,

sinA=cos(90A)

cosA=sin(90A) 

tanA=cot(90A) 

cosecA=sec(90A) 

secA=cosec(90A) 

cotA=tan(90A) 

Hence,sin55+cos20+cot70+cosec85=cos35+sin70+tan20+sec5

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