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Question

Find the unit vectors perpendicular to the following pair of vectors:
2i+j+k, i2j+k

A
135(3ij5k)
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B
135(3i+j5k)
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C
127(ij5k)
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D
127(ij+5k)
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Solution

The correct option is C 135(3ij5k)
a=2^i+^j+^k

b=^i^2j+^k

Vector perpendicular to Given vectors a,b

a×b=∣ ∣ ∣^i^j^k211121∣ ∣ ∣

a×b=^i(1(2))^j(21)+^k(41)

a×b=3^i^j^5k

Unit vector required is ^3i^j5^k3^i^j5^k=135(3^i^j^5k)

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