Question

Find the value
4[1 – $si{n}^2\theta$] [1 + $ta{n}^2\theta$]

• A. 4
• B. 1
• C. 2
• D. 0

Answer 1

The correct option is A

4

We know that (1 - $si{n}^2\theta$ = $co{s}^2\theta$ and 1 + $ta{n}^2\theta$ = $se{c}^2\theta$)

4[1 – $si{n}^2\theta$] [1 + $ta{n}^2\theta$] = $4co{s}^2\theta \times se{c}^2\theta =4$