Question

Find the value of
$\left[\right(3+4–6÷2+2)+(9÷3+6\times 5)÷11].$

• A. 11
• B. 5
• C. 9
• D. 8

Answer 1

The correct option is C

9

As we know, order of operation of BODMAS is as follows

Brackets Of Division Multiplication Addition Subtraction

Applying the same logic in the given expression,

$\left[\right(3+4–6÷2+2)+(9÷3+6\times 5)÷11]$

$=\left[\right(3+4-3+2)+(3+6\times 5)÷11]$

$=\left[\right(3+4-3+2)+(3+30)÷11]$

$=\left[\right(9-3)+33÷11]$

$=[6+3]$

$=9$