Find the value of 52 xyz xy - yz - xz - y2z - x - 104xy xy - xz - yz - y2-2 Marks-

52xyz(xy+yz+xz+y^2)(z+x)÷ 104xy(xy+xz+yz+y^2) =52xyz (xy + yz + xz + y^2)(z + x)/104xy (xy + xz + yz + y^2) =z (xy + yz + xz + y^2)(z + x)/2(xy + yz + xz + y^ ...

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Byju's Answer

Standard VIII

Mathematics

Division of Polynomials

Find the valu...

Question

Find the value of $52 x y z (x y + y z + x z + y^{2}) (z + x) \div 104 x y (x y + x z + y z + y^{2})$ . $[2 M a r k s]$

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Solution

$52 x y z (x y + y z + x z + y^{2}) (z + x) \div 104 x y (x y + x z + y z + y^{2})$

$= \frac{52 x y z (x y + y z + x z + y^{2}) (z + x)}{104 x y (x y + x z + y z + y^{2})}$

$= \frac{z (x y + y z + x z + y^{2}) (z + x)}{2 (x y + y z + x z + y^{2})}$ $[1 M a r k]$

$= \frac{1}{2} (z) (x + z)$

$∴$ the required value is $\frac{z (z + x)}{2}$ $[1 M a r k]$

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Similar questions

Q. Find the product:
(x – y − z) (x² + y² + z² + xy – yz + xz)

Q. The value of 52 xyz (xy + yz + xz +

y^{2}

)(z + x) + 104xy (xy + xz + yz +

y^{2}

) is

___

The value of $52 x y z (x y + y z + x z + y^{2}) (z + x) \times 104 x y (x y + x z + y z + y^{2})$ is:

Simplify the expression: \frac{52 w x y z (x y + y z + x z + y^{2}) (z + x)}{104 x y (x y z + x z^{2} + y z^{2} + y^{2} z)}

Q. If

x^{2} + x y + x z = 135, y^{2} + y z + x y = 351

and

z^{2} + x z + y z = 243

, then

x^{2} + y^{2} + z^{2} = ?

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Find the value of 52xyz(xy+yz+xz+y2)(z+x)÷104xy(xy+xz+yz+y2). [2 Marks]

52xyz(xy+yz+xz+y2)(z+x)÷104xy(xy+xz+yz+y2) =52xyz (xy + yz + xz + y2)(z + x)104xy (xy + xz + yz + y2) =z (xy + yz + xz + y2)(z + x)2(xy + yz + xz + y2) [1 Mark] =12(z)(x+z) ∴ the required value isz(z+x)2 [1 Mark]

Find the value of $52 x y z (x y + y z + x z + y^{2}) (z + x) \div 104 x y (x y + x z + y z + y^{2})$ . $[2 M a r k s]$