Question

Find the value of $\left(6x^6\right)\times (-2x^2{y}^3)\times (-24x{y}^2)$, when x = 1 and y = 2.

• A. 8966
• B. 9216
• C. 9612
• D. 8536

Answer 1

The correct option is B 9216

$\left(6x^6\right)\times (-2x^2{y}^3)\times (-24x{y}^2)$
$=[6\times (-2)\times (-24\left)\right]\times (x^6\times x^2\times x)\times (y^3\times y^2)$
Using the laws of indices, $a^m\times a^n=a^{(m+n)}$.
$=288\times \left(x^{(6+2+1)}\right)\times \left(y^{(3+2)}\right)$
$=288\times x^9\times y^5$
$=288x^9{y}^5$
Substituting the value of x = 1 and y = 2 in the above expression, we get
$=288\times (1{)}^9\times (2{)}^5$
$=288\times 1\times 32$
= 9216