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Question

Find the value of 99×101 using standard identity.

A
9999
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B
9989
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C
9979
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D
1009
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Solution

The correct option is A 9999
Given, 99×101=(1001)(100+1).

We know, (a+b)(ab)=a2b2.

Then,
99×101=(1001)(100+1)
=(100)212
=100001
=9999.

Therefore, option A is correct.

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