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Question

Find the value of (997)2 using algebraic identities.

A
994009
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B
996009
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C
940009
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D
946009
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Solution

The correct option is A 994009

We can write (997)2 as (10003)2.

We know that (ab)2=a2+b22ab.

Hence (10003)2=(1000)2+(3)22(1000)(3)
= 1000000 + 9 - 6000 = 994009


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