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Question

Find the value of a using the suitable algebraic identity, if  10a=602402.
  1. 200


Solution

The correct option is A 200
Here, 
602402 can be written in the algebraic form x2y2=(x+y)×(xy)
602402=(60+40)×(6040)
602402=100×20
602402=2000
Now, 
10a=2000
a=200010
a=200

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