Find the value of 3 - 2i i6 - i7 1 - i11

Let #160; Z=(3 + 2i) (i^6 i^7) (1 + i^11 ) #160; #160; #160; #160; =(3 + 2ii^2) (i^6 i^7) (1 + i^11 ) #160; #160; #160; ...

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Higher Order Derivatives

Find the valu...

Question

Find the value of $(3 + \frac{2}{i}) (i^{6} - i^{7}) (1 + i^{11})$

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Solution

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I_{n} = \int_{0}^{\frac{π}{4}} {tan}^{n} x dx

I_{9} + I_{11}

I_{n} = \int_{0}^{\frac{π}{4}} {tan}^{n} x dx

I_{9} + I_{11}

i^{2} = - 1

(i^{10} - \frac{1}{i^{11}}) + (i^{11} - \frac{1}{i^{12}}) + (i^{12} - \frac{1}{i^{13}}) + (i^{13} - \frac{1}{i^{14}}) + (i^{14} + \frac{1}{i^{15}})

∣ ∣ ∣ ∣ \begin{matrix} 1 + i & 1 - i & 1 1 - i & i & 1 + i i & 1 + i & 1 - i \end{matrix} ∣ ∣ ∣ ∣

∣ ∣ ∣ ∣ \begin{matrix} 1 + i & 1 - i & i 1 - i & i & 1 + i i & 1 + i & 1 - i \end{matrix} ∣ ∣ ∣ ∣ =

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