Find the value of 'c' if the distance between the point (c, 4) and the origin is 5 units and c > 0.

-3

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Solution

The correct option is B 3

For the point (c,4)
x - coordinate is c and
y - coordinate is 4
Distance from origin to the point is 5 units.
According to distance formula:
$c^{2} + 16 = 5^{2}$ ,

$\Rightarrow c^{2}$ = 9.
$\Rightarrow c = \pm 3$
$∵$ c > 0
Therefore, the value of c = +3.

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Find the value of 'c' if the distance between the point (c, 4) and the origin is 5 units and c > 0.

The correct option is B 3 For the point (c,4) x - coordinate is c and y - coordinate is 4 Distance from origin to the point is 5 units. According to distance formula: c2+16=52, ⇒c2 = 9. ⇒c=± 3 ∵ c > 0 Therefore, the value of c = +3.

The correct option is B 3

For the point (c,4)
x - coordinate is c and
y - coordinate is 4
Distance from origin to the point is 5 units.
According to distance formula:
$c^{2} + 16 = 5^{2}$ ,

$\Rightarrow c^{2}$ = 9.
$\Rightarrow c = \pm 3$
$∵$ c > 0
Therefore, the value of c = +3.