Find the value of cos19°59'.
(Refer the trigonometric table for the values)

0.9598

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0.9398

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0.9938

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0.9893

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Solution

The correct option is A 0.9398
We can write,
19°59' = 19°54' + 5'
From the table we have, cos19°54' = 0.9403
Mean difference for, 5′ = 5

cos19°54' = 0.9403
- 5′ = 5 (Mean difference to be subtracted for cosine)
____________________
cos19°59' = 0.9398

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