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Question

Find the value of XY for the complex [CoBr2(CN)(NO2)(H2O)(NH3)] 
where:
X = Number of compounds when both Br are at cis position. 
Y = Number of compounds when both Br are at trans position. 


Solution

[CO(Br)2(CN)(NO2)(H2O)(NH3)]
NO2and CNboth are ambidentate ligands. 
Br at trans position (optically inactive).
Br at cis position (optical active complex)
The number of geometrical isomers  keeping Br at cis position is 6 and all of them are optically active.
So there are twelve cis isomers. 
 X=12Y=3 (optical inactive complex)

XY=123=41
XY=4

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