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Question

Find the value of 28a3b3c3÷52ab2c3

A
7a2b13
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B
2a2b
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C
13a2b7
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D
7ab13
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Solution

The correct option is D 7a2b13
28a3b3c3÷52ab2c3=4×7×a3b3c34×13×ab2c3

=713a31b32c33

=713a2b1c0

=7a2b13

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