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Question

Find the value of 43tan260+3cos2302sec23034cot260


  1. 313

  2. 13

  3. 3

  4. 213


Solution

The correct option is A

313


43tan260+3cos2302sec23034cot260

= 43(3)2+3(32)22(23)234(13)2

= 43×3+3×342×433413

= 4+948314

= 4+948314

= 103

= 313

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