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Question

Find the value of cos3Acos3AcosA + sin3Asin3AsinA


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Solution

Given expression requires the values of sin3A & cot3A

sin3A = 3sinA - 4sin3A

cos3A = 4cos3A - 3cosA

Substituting the value of sin 3A and cos 3A

Expression = cos3A(4cos3A3cosA)cosA + sin3A3sinA4sin3AsinA

cos3A4cos3A+3cosAcosA + 3sin3A+3sinAsinA

3cos3A+3cosAcosA + 3sinA3sin3AsinA

-3cos2A + 3 + 3 -3sin2A

6 - 3 (sin2A+cos2A)

6 - 3 = 3


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