Question

Find the value of k for which x2–4x+k=0 has coincident roots.0 -2 4 -4

Solution

The correct option is C 4  For, x2–4x+k=0, value of discriminant D = (4)2–4k=16−4k  The roots of quadratic equation are co-incident only when D =0.  ⇒ 16 - 4k = 0  ⇒ ​ k = 4

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