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Question

Find the value of limx0120.tan xxx3x3

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Solution

We will sove this problem using the expansion of tanx

tan x=x+x33+2x515+....

limit=limx0120×(x+x33+2x515....xx3x3)

=limx0120×(2x33+2x515....x3)

=120limx0(23+215x2.....)

=120×(23)

=80


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