Find the value of limx→0(1+x)5−1x
We will solve this by using the expansion of (1+x)5.
We saw it in binomial theorem that (a+b)n can be expanded as (a+b)n=an+nc1 an−1b+.....bn.
We don't need all the terms of (1+x)5.
We don't need all the terms of (1+x)5 because they will become zero once we substitute x=0