Find the value of P if the pair of L.E is coincident.
$x - 2 y = - 2 a n d P x - 8 y = - 8$
4

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Solution

The correct option is A 4
Given,
Pair of linear equations:
$x - 2 y = - 2 a n d P x - 8 y = - 8$

$a_{1} = 1, a_{2} = P; b_{1} = - 2, b_{2} = - 8; c_{1} = - 2, c_{2} = - 8$

$∴ \frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$

$\Rightarrow \frac{1}{P} = \frac{- 2}{- 8} = \frac{- 2}{- 8}$

$\Rightarrow \frac{1}{P} = \frac{- 2}{- 8}$

$\Rightarrow 2 P = 8$

$\Rightarrow P = 4$

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