Question

Find the value of the letters in the following question:


$8ABC-ABC5\_\_\_\_\_\_\_\_D488$

Answer 1

Given, $8ABC-ABC5\_\_\_\_\_\_\_\_D488$
In the ones column, C - 5 = 8
Obviously, 13 - 5 = 8, so C = 3
In the ten's column, B - (C + 1) = 8
$\Rightarrow$ B = 8 + C + 1
$\Rightarrow$ B = 8 + 3 + 1
$\Rightarrow$ B = 12 i.e. B = 2
In the hundred's column, A - (B + 1) = 4
$\Rightarrow$ A = 4 + B + 1
$\Rightarrow$ A = 4 + 2 + 1 = 7
In the thousand's column, 8 - A = D
$\Rightarrow$ 8 - 7 = D
$\Rightarrow$ D = 1
Hence, A = 7, B = 2, C = 3 and D = 1