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Question

Find the value of the unknown exterior angle $$x$$ in the following diagrams.
1645597_afd35f9d3025430db1fc22e6689cec97.png


Solution

Sum of all angles of a $$\Delta le  = 180^o$$
$$30^o + 60^o + \angle ABC = 180^o$$
$$\therefore \angle ABC = 90^o$$
Now, $$x + \angle ABC = 90^o$$
$$\therefore x = 90^o$$

$$Or$$
Since, Exterior angle$$=$$Sum of interior opposite angles, therefore $$x=60^o+30^o=90^o$$.

1339205_1645597_ans_96b19004c2cf4d6496550b4f4050b516.png

Mathematics
NCERT
Standard VII

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