Find the value of x.
26∘
In ΔABC,
∠ACB+∠CBA+∠BAC=180∘ .... {angle sum property}
⇒∠ACB+35∘+39∘=180∘
⇒∠ACB=∠180∘−(35∘+39∘
= 180∘−74∘
= 106∘
⇒∠DCE=∠ACB=106∘ ..... {vertically opposite angles}
In ΔDEC,
∠DCE+∠CED+∠EDC=180∘ ..... {angle sum property}
⇒x=180∘−(106∘+48∘)=26∘