Find the value of $(x + 2 y)$ satisfying the equations,
$x + y = 3$ and $3 x - 2 y = 4$ .

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Solution

Given equations are
$x + y = 3 - - - e q n (1)$
$3 x - 2 y = 4 - - - e q n (2)$

Multiplying $e q n (1)$ with $2$ we get: $2 x + 2 y = 6 - - - e q n (3)$

Adding $e q n (3)$ and $e q n (2)$ gives us value $x = 2$

Substituting $x = 2$ in $e q n (1)$ , we get $y = 1$

So we get $(x + 2 y) = 2 + (2 \times 1) = 4$

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