Find the value of $x$ if $(20 x + 3) - (5 x - 7) = 40$ .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2
We have to find the value of $x$ in the given equation.

$(20 x + 3) - (5 x - 7) = 40$

Let's first open the brackets
$⟹ 20 x + 3 - 5 x + 7 = 40$

Now, transpose the variables on the one side and constants on the other side of the equation.
$⟹ 20 x - 5 x = 40 - 3 - 7$
$⟹ 15 x = 30$ [Transposing 15 to RHS]
$⟹ x = \frac{30}{15} = 2$

Hence, option 'c' is correct.

Suggest Corrections

Similar questions

lim x \to 0 \frac{1 - 4^{x} - 5^{x} + 20^{x}}{\sqrt{2 cos x + 7} - 3}

The sum of all zeroes of the polynomial p(x) = $5 x^{5} - 20 x^{4} + 5 x^{3} + 50 x^{2} - 20 x - 40$ is

and the product is

x = 2

3 (x + 2) + 5 x - 7

2 x^{3} + 3 x^{2} - 5 x + 7

x = 2.05

Join BYJU'S Learning Program