Find the value of $x$ in the following equations.

(i) 4 $x$ + 5 = 25

(ii) $(7 x + 8) \div 7 = 8$

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Solution

(i) 4x + 5 = 25

$\Rightarrow$ 4x = 25 - 5

$\Rightarrow$ 4x = 20 ....(0.5 mark)

Divide by 4 on both sides, $x = \frac{20}{4} = 5 . . . (0.5 m a r k s)$

(ii) $(7 x + 8) \div 7 = 8$

$\Rightarrow \frac{7 x + 8}{7} = 8 \Rightarrow 7 x + 8 = 8 \times 7 = 56 . . . (0.5 m a r k) N o w t r a n s p o sin g t h e 8 t o R H S \Rightarrow 7 x = 56 - 8 = 48 N o w t r a n s p o sin g t h e 7 t o R H S \Rightarrow x = \frac{48}{7} = 6 \frac{6}{7} . . . (1 m a r k)$

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Solve the following system of equations in R.

$\frac{2 x + 1}{7 x - 1} > 5, \frac{x + 7}{x - 8} > 2$

Find the value of ' $x$ '.

(i) $4 x + 5 = 25$

(ii) $x - 2 \frac{1}{3} = 5 \frac{1}{2}$

(iii) $(7 x + 8) \div 7 = 8$

4 x + 5 = 25

x - 2 \frac{1}{3} = 5 \frac{1}{2}

(7 x + 8) \div 7 = 8

{\sqrt{2 x}}^{2} + 7 x + 5 \sqrt{2} = 0

2 x^{2} - x + \frac{1}{8} = 0

x

4 x + 5 = 25

x - 2 \frac{1}{3} = 5 \frac{1}{2}

(7 x + 8) \div 7 = 8

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