Find the value of $x$ :
$(2 x - 7) (3 x + 1) = (2 x - 5) (3 x + 2)$

Open in App

Solution

Given, $(2 x - 7) (3 x + 1) = (2 x - 5) (3 x + 2)$

$\Rightarrow 6 x^{2} + 2 x - 21 x - 7 = 6 x^{2} + 4 x - 15 x - 10$ ...[By Distribution Law]

$\Rightarrow - 19 x - 7 = - 11 x - 10$ ...[Cancelling common terms and simplifying]

$\Rightarrow - 19 x + 11 x = - 10 + 7$ ...[Transposing $x$ terms to one side]

$\Rightarrow - 8 x = - 3$ ...[On simplifying]

$∴ x = \frac{- 3}{- 8} = \frac{3}{8} .$

Suggest Corrections

Similar questions

x

\frac{1}{2 (2 x + 3 x)} + \frac{12}{7 (3 x - 2 x)} = \frac{1}{2}

\frac{1}{2 (2 x + 3 y)} + \frac{12}{7 (3 x - 2 y)} = \frac{1}{2}, \frac{7}{(2 x + 3 y)} + \frac{4}{(3 x - 2 y)} = 2

(2 x + 3 y)

5 - 2 x < 5 \frac{1}{2} - \frac{5}{3} x

lim x \to \infty {\frac{x^{2} + 2 x + 3}{2 x^{2} + x + 5}}^{\frac{3 x - 2}{3 x + 2}}

Find the non-negative root of ${(\frac{3 x - 1}{2 x + 3})}^{2} - 5 (\frac{3 x - 1}{2 x + 3}) + 4 = 0$

Join BYJU'S Learning Program