Find the value of $x - y^{x - y}$ when $x = 2$ and $y = - 2$ .

18

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- 18

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14

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- 14

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Solution

The correct option is D $- 14$
$x = 2, y = - 2$
$x - y^{x - y} - 2 - (- 2)^{2 - (- 2)} = 2 - (- 2)^{4} = 2 - 16 = - 14$

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\frac{1}{4}

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Factorise $(2 x - y)^{2} - 14 x + 7 y - 18$

x^{2} + 9 x + 14

x = - 2

(- 2)^{2} + 9 (- 2) + 14

\frac{x + y}{2} + \frac{3 x - 5 y}{4} = 2, \frac{x}{14} + \frac{y}{18} = 1

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