Question

Find the values of A, B and C in the following sum:

$5\frac{A}{7}+3\frac{1}{7}=B\frac{6}{C}$

• A. A = 5 ; B = 8 ; C = 14
• B. A = 5 ; B = 8 ; C = 7
• C. A = 7 ; B = 8 ; C = 7
• D. A = 7 ; B = 8 ; C = 14

Answer 1

The correct option is B A = 5 ; B = 8 ; C = 7

$\text{Whole part of the mixed number}5\frac{A}{7}=5$

$\text{Whole part of the mixed number}3\frac{1}{7}=3$

$⟹\text{Sum of the whole parts}=(5+3)=8$

$\text{Fractional part of the mixed number}5\frac{A}{7}=\frac{A}{7}$

$\text{Fractional part of the mixed number}3\frac{1}{7}=\frac{1}{7}$

$⟹\text{Sum of the fractional parts}=\frac{A}{7}+\frac{1}{7}=\frac{(A+1)}{7}$

$⟹5\frac{5}{7}+3\frac{1}{7}=8+\frac{(A+1)}{7}=8\frac{(A+1)}{7}$

$\text{Comparing the final sum with the given}\text{expression, we find:}$

$8\frac{(A+1)}{7}=B\frac{6}{C}$

$⟹A+1=6;B=8;C=7$

$⟹A=5;B=8;C=7$