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Question

Find the values of K if Area of the triangle is 4 sq. units and vertices are (k0) (40) (02) using determinants.

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Solution

12∣ ∣K01401021∣ ∣=±4
K=(02)0(0)+1(8)=±8
2K+8=±8
2K=88
2K=0
K=0
or 2K=88
2K=16
K=8

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