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Question

Find the values of the trigonometric ratio
tanθ=11

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Solution

According to question,

tanA=111=PB

Let hypotenuse , H=3k
So, perpendicular,P=2k

P2+B2=H2

H2=P2+B2
=(11k)2+(1k)2
=122k2

H=122k


cosA=BH
=1122


cotA=BP
=111


cosecA=HP
=12211


secA=HB
=1221


sinA=PH
=11122

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